9.1 Superclasses and Subclasses

A hierarchy of classes is created, extending attributes into subclasses of information (ie. Automobile –> Trucks and Sedans –> Ford, BMW, Nissan, Toyota).

Pre-Requisites

Before we start you need to remember what classes and methods are. Scopes of variables are also important to this section because you need to know which classes can access which variables before extending a variable across classes.

Scope of Variables:

Variables can be declared as private or public.

Popcorn Hack: What are scope do private and public variables allow?

Private	Public
only directly accessible within the class they are declared	accessible anywhere inside and outside their class

These are different types of variables. Only INSTANCE and STATIC variables can be declared as __ or __.

Variable Type	Definition	Scope within Class	Scope to Subclasses
local variables	variables within methods	cannot be accessed outside method	cannot be accessed outside class
instance variables	variables within a class but not inside a method	can be accessed in entire class	can be accessed in subclasses
static variables	variables that belong to a class, not instance	can be accessed in entire class	can be accessed in subclasses
parameter variables	variables specific in passing values to the method	cannot be accessed outside method	do not affect inheritance

Now we can go into class hierarchies.

Class Hierarchy

Definitions

Superclasses - a class that contains all the common __ and __ that could be shared among other classes (a blueprint for subclasses)
Subclasses - extends the __ to is specified by a superclass; can also have additional specific attributes
“Is-A” Relationship - the relationship when a subclass __ a superclass (ie. Automobile –> Sedan; a Sedan “is-a” automobile)

`extends` Keyword

extends the subclass from the superclass.

class Automobile {
  public String brand; // public instance var
  private String model; // private instance var

  public Automobile(String brand, String model) {
    this.brand = brand;
    this.model = model;
  }

  public void start() {
    System.out.println("Car is starting");
  }
}

class Truck extends Automobile {
  public int cargoCapacity; // subclass specific var

  // instance that is specific to the Truck subclass, with vars from Automobile class
  public Truck(String brand, String model, int cargoCapacity) {
    super(brand, model); // inherited vars
    this.cargoCapacity = cargoCapacity;
  }

  // specific method to Truck
  public void loadCargo() {
    System.out.println("Loading cargo into the truck");
  }
}

class Sedan extends Automobile {
  public boolean isLuxury; // subclass specific var

  // instance that is specific to the Sedan subclass, with vars from Automobile class
  public Sedan(String brand, String model, boolean isLuxury) {
    super(brand, model); // inherited vars
    this.isLuxury = isLuxury;
  }

  // specific method to Sedan
  public void accelerate() {
    System.out.println("Sedan is accelerating");
  }
}

public class Main {
    public static void main(String[] args) {
        Automobile car = new Automobile("Toyota", "Camry");
        Truck truck = new Truck("Ford", "F-150", 1000);
        Sedan sedan = new Sedan("BMW", "328i", true);

        // automobile methods and variables
        System.out.println(car.brand); // Accessing public variable
        // System.out.println(car.model); // compilation error because of the private var
        car.start();


        // truck methods and variables
        System.out.println(truck.brand); // inherited public var
        System.out.println(truck.cargoCapacity); // public var specific to truck
        truck.loadCargo();


        // sedan methods and variables
        System.out.println(sedan.brand); // inherited public var
        System.out.println(sedan.isLuxury); // public var specific to sedan
        sedan.accelerate();
    }
}

Main.main(null);

Toyota
Car is starting
Ford
1000
Loading cargo into the truck
BMW
true
Sedan is accelerating

This example shows how the Automobile class is extended twice, with the Truck and Sedan subclasses.

Popcorn Hack: If I were to declare a variable color that is private in the class Automobile, would I be able to extend and directly access that variable to the subclass Truck or Sedan?

A: No, you would need to encapsulate the private variable as shown above, through a method in the superclass and then inherit that var with super(), which will be explained later.

9.2 Writing Constructors for Subclasses

Learning Objectives

Constructors are not inherited
When a subclass’s constructor doesn’t explicitly call a superclass’s constructor using super, Java inserts a call to the superclass’s no-argument constructor.
The actual parameters passed in the call to the superclass constructor provide values that the constructor can use to initialize the object’s instance variables.
Regardless of whether the superclass constructor is called implicitly or explicitly, the process of calling superclass constructors continues until the Object constructor is called. At this point, all of the constructors within the hierarchy execute beginning with the Object constructor.

Important note: Constructors are NOT inherited by the subclass. See this in action below.

// TO BE INCLUDED EARLIER IN THE LESSON. IT IS NECESSARY FOR THE FUNCTIONALITY OF THIS SECTION.

class Vehicle {
    public int year;
    public String manufacturer;

    public Vehicle(int year, String manufacturer) { // constructor for parent class
        this.year = year;
        this.manufacturer = manufacturer;
    }

    public Vehicle() {
        this.year = 2000;
        this.manufacturer = "Unknown";
    }

    // method to be used later
    public void drive() {
        System.out.println("The driver is driving the car.");
    }
}

class Car extends Vehicle {
    public String model;

    public Car(String model) {
        this.model = model;
    }
}

public class VehicleDemonstration {
    public static void main(String[] args) {
        Car myCar = new Car("Altima");
        System.out.println("Year: " + myCar.year);
        System.out.println("Manufacturer: " + myCar.manufacturer);
        System.out.println("Model: " + myCar.model);
    }
}

VehicleDemonstration.main(null);

Year: 2000
Manufacturer: Unknown
Model: Altima

As you can see, the output uses the no-argument construction info from the base Vehicle constructor.

The super keyword can be used to change parent constructor values.

class NewCar extends Vehicle {
    public String model;

    public NewCar(int year, String manufacturer, String model) {
        super(year, manufacturer); // see the use of super here
        // what happens if you use no arguments with super()? see reminders below
        this.model = model;
    }
}

public class VehicleDemonstration2 {
    public static void main(String[] args) {
        NewCar myCar = new NewCar(2016, "Nissan", "Altima");
        System.out.println("Year: " + myCar.year);
        System.out.println("Manufacturer: " + myCar.manufacturer);
        System.out.println("Model: " + myCar.model);
    }
}

VehicleDemonstration2.main(null);

Year: 2016
Manufacturer: Nissan
Model: Altima

Key Reminders:

If you do call super() in your constructor, it has to be the first line of the constructor.
You cannot assign values to parent attributes/variables without using super().
If you call super() with no arguments, it will use the no-argument parent constructor. This also happens automatically if you don’t include any super() call.

9.3 Overriding Methods

Learning Objectives

Method overriding occurs when a public method in a subclass has the same method signature as a public method in the superclass.
Any method that is called must be defined within its own class or its superclass.
A subclass is usually designed to have modified (overwritten) or additional methods or instance variables.
A subclass will inherit all public methods from the superclass; these methods remain public in the subclass.

There are three options for methods to be used by subclasses:

Methods inherited from the parent class
Unique methods written for the subclass
Override parent methods to modify its implementation

The first two should make sense. Let’s see an example of overriding parent methods below.

public class NuroCar extends Vehicle {
    private String deliveryItem;

    // unique constructor
    public NuroCar(int year, String manufacturer, String deliveryItem) {
        super(year, manufacturer); // another use of super
        this.deliveryItem = deliveryItem;
    }

    // HERE is the overridden function
    public void drive() {
        System.out.println("This car is driving itself!");
    }
}

public class VehicleDemonstration3 {
    public static void main(String[] args) {
        NuroCar pizzaCar = new NuroCar(2023, "Nuro", "Pizza");
        // here's the call to the overridden function
        pizzaCar.drive();
    }
}

VehicleDemonstration3.main(null);

This car is driving itself!

This can be very helpful if you want a certain parent method to function slightly differently for a certain subclass.

Popcorn Hack

A parent class Animal is often used to show how subclasses can differ from their parent classes. An Animal parent class is provided in the cell below. Create a subclass of a certain species that overrides a parent method and uses `super` to call to the parent's constructor while adding its own unique attributes.

Hint:

public class Lion extends Animal {
    private int maneLength;

    // constructor with arguments specific to Lion
    public Lion(String species, int milesPerHour, int maneLength) {
        super(species, milesPerHour);
        this.maneLength = maneLength;
    }

    // override the move method
    @Override
    public void move() {
        super.move(); // Call the parent's move method using super
        System.out.println("It's known for its majestic " + this.maneLength + " inch mane.");
    }
}

|   public class Lion extends Animal {

cannot find symbol

  symbol:   class Animal

|       @Override

method does not override or implement a method from a supertype

|           super.move(); // Call the parent's move method using super

non-static variable super cannot be referenced from a static context

|           super.move(); // Call the parent's move method using super

cannot find symbol

  symbol: method move()

9.4 Super Keyword

Using the super keyword to call a superclass’s method.

public class Performer { //superclass
    public void practice(){
        System.out.println("Honing my craft!");
    }
    public void perform(){
        System.out.println("Performing for an audience!");
    }
}

public class Dancer extends Performer { //subclass
    public void perform(){
        System.out.println("Dancing on the stage!");
    }
}

public class BalletDancer extends Dancer { //subclass
    public void jete(){
        System.out.println("Leaping...");
    }
    public void pirouette(){
        System.out.println("Spinning...");
    }
    public void perform(){
        jete();
        pirouette();
    }
        public static void main(String[] args){
            BalletDancer derrick = new BalletDancer();
            derrick.practice();
            derrick.perform();
        }
}

System.out.println("BalletDancer class: ");
BalletDancer.main(null);

BalletDancer class: 
Honing my craft!
Leaping...
Spinning...

public class Performer { //superclass of Dancer class
    public void practice(){
        System.out.println("Honing my craft!");
    }
    public void perform(){
        System.out.println("Performing for an audience!");
    }
}

public class Dancer extends Performer { //superclass of BalletDancer class
    public void perform(){
        System.out.println("Dancing on the stage!");
    }
}

public class BalletDancer extends Dancer {
    public void jete(){
        System.out.println("Leaping...");
    }
    public void pirouette(){
        System.out.println("Spinning...");
    }
    public void perform(){ 
        perform();//Why is this wrong?
        jete();
        pirouette();
    }
        public static void main(String[] args){
            BalletDancer derrick = new BalletDancer();
            derrick.practice();
            derrick.perform();
        }
}

System.out.println("BalletDancer class: ");
BalletDancer.main(null);

Note:

Super keyword can be placed in any order as it prints out chronologically.

public void perform(){ 
    super.perform();
    jete();
    pirouette();
}

"Honing my craft!
Dancing on the stage!
Leaping...
Spinning..."

However, if we were to write:

public void perform(){ 
    jete();
    pirouette();
    super.perform();
}

"Honing my craft!
Leaping...
Spinning...
Dancing on the stage!"

What if we use 2 super keywords?

public class Performer {
    public void practice(){
        System.out.println("Honing my craft!");
    }
    public void perform(){
        System.out.println("Performing for an audience!");
    }
}

public class Dancer extends Performer {
    public void perform(){
        super.perform();
        System.out.println("Dancing on the stage!");
    }
}

public class BalletDancer extends Dancer {
    public void jete(){
        System.out.println("Leaping...");
    }
    public void pirouette(){
        System.out.println("Spinning...");
    }
    public void perform(){
        super.perform();
        jete();
        pirouette();
    }

    public static void main(String[] args){
        BalletDancer derrick = new BalletDancer();
        derrick.practice();
        derrick.perform();
    }
}



System.out.println("BalletDancer class: ");
BalletDancer.main(null);

BalletDancer class: 
Honing my craft!
Performing for an audience!
Dancing on the stage!
Leaping...
Spinning...

Popcorn Hack

Create a subclass and a superclass by calling the methods from the superclass from the subclass using the keyword super.

public class Performer {
    public void practice(){
        System.out.println("Honing my craft!");
    }
    public void perform(){
        System.out.println("Performing for an audience!");
    }
}

public class Dancer extends Performer {
    public void perform(){
        super.perform();
        System.out.println("Dancing on the stage!");
    }
}

public class BalletDancer extends Dancer {
    public void jete(){
        System.out.println("Leaping...");
    }
    public void pirouette(){
        System.out.println("Spinning...");
    }
    public void perform(){
        super.perform();
        jete();
        pirouette();
    }

    public static void main(String[] args){
        BalletDancer derrick = new BalletDancer();
        derrick.practice();
        derrick.perform();
    }
}

BalletDancer.main(null);

Honing my craft!
Performing for an audience!
Dancing on the stage!
Leaping...
Spinning...

9.5 Creating References Using Inheritance Hierarchies

Inheritance Hierarchies is the idea that:

If we have a public superclass (A) that then has a public subclass (B) and that public subclass then has another public subclass (C), then the subclass C is also a subclass of the superclass A and so subclass C is extending superclass A

Here is an example of this:

// Class Declarations:

// Superclass (A)
public class Vehicles{}
// Subclass (B)
public class Car extends Vehicles{}
// Subclass (C)
public class Sedan extends Car{}
// Subclass (D)
public class Truck extends Vehicles{}

Here is a diagram displaying this relationship:

Inheritance Hierarchy Example

This diagram shows the the vehicle superclass which then has two subclasses: Car and Truck, however, Car has another subclass called Sedan
Based on this diagram, we know that Truck has a “is-a” relationship with Vehicle, Car also has a “is-a” relationship with Vehicle, and since Car has an “is-a” relationship with Vehicle, so does Sedan
So Sedan also has a “is-a” relationship with Vehicle

If we assume that all of the class contain a constructor with no arguments, this then allows for us to declare a superclass reference variable to hold a subclass object:

Vehicles v1 = new Truck();
Vehicles v2 = new Car();

// instead of doing
Car v3 = new Sedan();
// We have the option to do this instead
Vehicles v4 = new Sedan();

However, it is important to remember that you can’t declare a Subclass variable and put in a Superclass object

// don't do this
Sedan v5 = new Vehicle();

Popcorn Hack: Using a superclass and subclasses of your choice, assuming that the classes contain a constructor with no arguments, create Class Declarations and Superclass References

// Superclass: Vehicle
public class Vehicle {
    private String type;

    public Vehicle() {
        this.type = "Unknown";
    }

    public Vehicle(String type) {
        this.type = type;
    }

    public void describe() {
        System.out.println("This is a " + type);
    }
}

// Subclass: Truck
public class Truck extends Vehicle {
    public Truck() {
        super("Truck");
    }

    public void loadCargo() {
        System.out.println("Loading cargo...");
    }
}

// Subclass: Car
public class Car extends Vehicle {
    public Car() {
        super("Car");
    }

    public void startEngine() {
        System.out.println("Starting the engine...");
    }
}

// Subclass: Sedan
public class Sedan extends Car {
    public Sedan() {
        super("Sedan");
    }

    public void openTrunk() {
        System.out.println("Opening the trunk...");
    }
}

public class Main {
    public static void main(String[] args) {
        Vehicle v1 = new Truck();
        Vehicle v2 = new Car();
        Vehicle v4 = new Sedan();

        v1.describe(); // Output: This is a Truck
        v2.describe(); // Output: This is a Car
        v4.describe(); // Output: This is a Sedan

        // The following lines would cause compilation errors
        // v1.loadCargo();
        // v2.startEngine();
        // v4.openTrunk();
    }
}

Main.main(null);

Why would we want to do this?

When doing object oriented programming, we are able to create a superclass with common attributes and then have subclasses with more specific traits
By doing this, we get rid of code redundancy and it also makes the easier to reuse common aspects without needing to write them out every time while still presenting the option to override any attribute from the superclass to better represent the subclass
All the subclasses adhere to one superclass so this makes updates to code much easier and allows you to take advantage of polymorphism to unify the code and allow for more flexible and manageable code (more about this in 9.6)

Here is a Complete Example of the Inheritance Hierarchy from above:

class Vehicle {
    private String brand; // private instance variable
    private int year; // private instance variable

    public Vehicle(String brand, int year) {
        this.brand = brand;
        this.year = year;
    }

    public void displayInfo() { // common variables for each vehicle
        System.out.println("Brand: " + brand);
        System.out.println("Year: " + year);
    }
}

class Truck extends Vehicle {
    // feature that only a truck can have
    private double maxLoadCapacity;

    public Truck(String brand, int year, double maxLoadCapacity) {
        super(brand, year); // Inherits the variables from superclass
        this.maxLoadCapacity = maxLoadCapacity;
    }

    @Override // Override allows for displayInfo to now also show the trait specific to the Truck while still keeping the main variables
    public void displayInfo() {
        super.displayInfo(); // Reuse the displayInfo method from the superclass
        System.out.println("Max Load Capacity: " + maxLoadCapacity + " tons");
    }
}

class Car extends Vehicle {
    // something that cars have
    private int numberOfDoors;

    public Car(String brand, int year, int numberOfDoors) {
        super(brand, year);
        this.numberOfDoors = numberOfDoors;
    }

    @Override // Override allows for displayInfo to now also show the trait specific to the Car while still keeping the main variables
    public void displayInfo() {
        super.displayInfo(); // Reuse the displayInfo method from the superclass
        System.out.println("Number of Doors: " + numberOfDoors);
    }
}

class Sedan extends Car {
    // Sedan is luxury so trait specific to sedan
    private boolean leatherSeats;

    public Sedan(String brand, int year, int numberOfDoors, boolean leatherSeats) {
        super(brand, year, numberOfDoors);
        this.leatherSeats = leatherSeats;
    }

    @Override // Override allows for displayInfo to now also show the trait specific to the Sedan while still keeping the main variables
    public void displayInfo() {
        super.displayInfo(); // Reuse the displayInfo method from the superclass
        System.out.println("Leather Seats: " + leatherSeats);
    }
}

public class Main {
    public static void main(String[] args) {
        Vehicle v1 = new Truck("Ford", 2023, 10.5);
        Vehicle v2 = new Car("Toyota", 2023, 4);
        Vehicle v3 = new Sedan("Honda", 2023, 4, true);

        System.out.println("Truck Information:");
        v1.displayInfo();
        
        System.out.println("\nCar Information:");
        v2.displayInfo();
        
        System.out.println("\nSedan Information:");
        v3.displayInfo();
    }
}
Main.main(null)

Truck Information:
Brand: Ford
Year: 2023
Max Load Capacity: 10.5 tons

Car Information:
Brand: Toyota
Year: 2023
Number of Doors: 4

Sedan Information:
Brand: Honda
Year: 2023
Number of Doors: 4
Leather Seats: true

Popcorn Hack: In your own words describe the importance of Inheritance Hierarchies

Inheritance promotes code reuse by allowing subclasses to inherit existing code from their superclasses. This means that common attributes and behaviors can be defined in a superclass and reused across multiple subclasses, reducing the need for redundant code.

9.6 Polymorphism

Learning Objectives

MOD-3.D: Call methods in an inheritance relationship.
MOD-3.D.1: Utilize the Object class through inheritance.
MOD-3.D.2: At compile time, methods in or inherited by the declared type determine the correctness of a non-static method call.
MOD-3.D.3: At run-time, the method in the actual object type is executed for a non-static method call.

What is Polymorphism?

Polymorphism is a greek word meaning many-formed (poly=many, morph=form). In the context of programming, Polymorphic behavior is defined as being able to reference objects of different types at different points during compilation.

One example of Java polymorphism, is our ability to store references to objects instantiated from any class AND its subclasses in a variable. Another example is for methods, where we override the behavior of a method in a subclass such that it differs from the parent class. We successfully perform polymorphism when we override non-static methods and execute them from the correct, corresponding class at runtime.

Here is a simple example of polymorphism:

// This is our Parent class
class Shape {
    public void draw() {
        System.out.println("Drawing a shape");
    }
}

// Subclass 1
class Circle extends Shape {
    @Override
    public void draw() {
        System.out.println("Drawing a circle");
    }
}

// Subclass 2
class Rectangle extends Shape {
    @Override
    public void draw() {
        System.out.println("Drawing a rectangle");
    }
}

public class Main {
    public static void main(String[] args) {
        
        // Here we have reference variables circle and rectangle defined with static type "Shape"
        Shape circle = new Circle();            // Circle has dynamic type "Circle"
        Shape rectangle = new Rectangle();      // Rectangle has dynamic type "Rectangle"
        
        // Calling the draw() method
        circle.draw();    // Output: Drawing a circle
        rectangle.draw(); // Output: Drawing a rectangle
    }
}

Main.main(null);

Even though the circle and rectangle have identical data-types, the compiler knows to call the correct method at run-time. We have successfully performed polymorphism

Popcorn hack

Create any example of polymorphism, perferably with a class from your project, with corresponding methods and attributes as well.

// Shape class
class Shape {
    public double calculateArea() {
        return 0; // This will be overridden by subclasses
    }
}

// Rectangle subclass
class Rectangle extends Shape {
    private double length;
    private double width;

    public Rectangle(double length, double width) {
        this.length = length;
        this.width = width;
    }

    @Override
    public double calculateArea() {
        return length * width;
    }
}

// Circle subclass
class Circle extends Shape {
    private double radius;

    public Circle(double radius) {
        this.radius = radius;
    }

    @Override
    public double calculateArea() {
        return Math.PI * Math.pow(radius, 2);
    }
}

// Main class to demonstrate polymorphism
public class Main {
    public static void main(String[] args) {
        Shape shape1 = new Rectangle(5, 10);
        Shape shape2 = new Circle(7);

        System.out.println("Area of Rectangle: " + shape1.calculateArea());
        System.out.println("Area of Circle: " + shape2.calculateArea());
    }
}
Main.main(null);

Area of Rectangle: 50.0
Area of Circle: 153.93804002589985

Static and Dynamic types

Typically in Java, a reference variable storing an object instantiated from a child class can only store other objects of that class. If we try to store an object of another class, we’d get an error i.e.

Integer myNumber = new Integer(6);      // Instantiates an Integer object
System.out.println(myNumber);           // Would print Integer type 6 normally
myNumber = new Double(6.1);             // Compile error occurs, incompatible types
System.out.println(myNumber);           // This line is not reached

But what if we want want a reference variable to store objects of other classes? We get an error

Compile-time vs Runtime methods

Sometimes, when we perform polymorphism, we have to be careful to distinguish between our compile time and run-time methods. When we instantiate a dynamic variable that is of a different type from our static variable, our program at run time will attempt to search for the methods and attributes in the superclass, NOT the child class that we created. Although the compiled program will still output the correct outputs of the method in the child class, it will not be able to find a method that exists in the child class but not in the parent class.

To resolve this issue, we need use Down-casting.

Downcasting: Essentially telling the compiler to refer to a variable’s subclass (the programmer specifies this), instead of the static type. We are telling the compiler to search our dynamic type for the methods and attributes that we want to access.

Below is an example of compile versus run-time methods and downcasting that I used in our group’s project.

import java.util.HashMap;
// This is our parent class for all child classes that make up a graph
public class GraphObject {
    private int value;

    // constructor
    public GraphObject(int value) {
        this.value = value;
    }

    // getter method
    public int getValue() {
        return this.value;
    }

    // setter method
    public void setValue(int value) {
        this.value = value;
    }

    // Method overloading to print object to terminal
    @Override
    public String toString() {
        return Integer.toString(this.value);
    }
}

// This is our child class. Represents a vertex or a node in a graph
public class GraphNode extends GraphObject {
    private HashMap<Integer,Integer> edges;     // Hashmap of destination vertices and weights of paths <Target:Weight>

    // Constructor of child class
    public GraphNode(int value, HashMap<Integer,Integer> edges){
        super(value);                           // super keyword to run constructor of parent class, which sets the value of the node
        this.edges = edges;                     // adds any needed edges
    }

    public HashMap<Integer,Integer> getEdges() {
        return this.edges;
    }

    public void addEdge(int targetId, int weight) {
        this.edges.put(targetId, weight);
    }

    public void removeEdge(int targetId) {
        this.edges.remove(targetId);
    }
    
    // Overloading the toString method of the parent class, using super to get the output of the parent class
    @Override
    public String toString() {
        return "GraphNode[value=" + super.toString() + ",edges=" + this.edges + "]";
    }
} 
HashMap<Integer, Integer> node1Connections = new HashMap<Integer, Integer>();
node1Connections.put(2, 7);
node1Connections.put(3, 2);
node1Connections.put(4, 10);
GraphObject node1 = new GraphNode(1, node1Connections);
System.out.println(node1.toString());
((GraphNode)node1).addEdge(5,6);        // Here, we downcast node1, which is a GraphObject, to what it references, which is GraphNode
// node1.addEdge(5,6);                  // This wouldn't work as the compiler attempts to find addEdge() in GraphObject, which it can't, throwing an error  
System.out.println(node1.toString());

Popcorn Hacks

Define each of the following terms in your own words
- Downcasting
- Static Type
- Dynamic Type
- Polymorphism
- Compile-time method
- Run-time method

// Do popcorn hack here

Downcasting in object-oriented programming is the process of converting a reference of a superclass type to a reference of a subclass type. This allows you to access specific methods or properties that are unique to the subclass.
The static type is used by the Java compiler to perform type checking and ensure that operations and method calls are compatible with the declared types.
The actual type of an object at runtime.
It enables a single interface or method to be used for different data types or classes.
However, there is a concept known as “compile-time binding” or “static binding,” which is a form of polymorphism that occurs at compile time.
A method that is invoked or executed during the execution of a program, as opposed to being determined at compile time.

9.7 Object Superclass

The Object class is the superclass of all other classes as well as data types and is a part of the java.lang package
If a parent class doesn’t specify by using the extends keyword, the class will inherit from the Object
String toString() and boolean equals(object other) are the most frequently used and subclasses of Object override the equals and toString methods by using class-specific implementations

Normally when you use the toString method without overriding it, it returns a hash code value as seen in the example below:

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }
}

public class ToStringNoOverride {
    public static void main(String[] args) {
        Person person = new Person("Alice", 25);
        // When you print this out, it will return the hash code since its using the default method for toString
        System.out.println(person);
    }
}
ToStringNoOverride.main(null)

REPL.$JShell$18$Person@4da14117

However, we can fix this by creating a new method by overriding the normal toString method and building our own representation of the object

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    @Override
    public String toString() { // We override the toString method here
        return "Person Name: " + name + "\nPerson Age: " + age; // We then add our own custom string representation
    }
}

public class ToStringOverride {
    public static void main(String[] args) {
        Person person = new Person("Alice", 25);

        // When you print the person object, it calls the overridden toString method we made
        System.out.println(person);
    }
}
ToStringOverride.main(null)

Person Name: Alice
Person Age: 25

Now, we want to compare 2 people by using boolean equals(Object other) and determine if they are the same

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    @Override
    public String toString() {
        return "Person Name: " + name + "\nPerson Age: " + age;
    }
}

public class EqualsNoOverride {
    public static void main(String[] args) {
        Person person1 = new Person("Alice", 25);
        Person person2 = new Person("Bryce", 25);

        System.out.println("Person 1 Age equals Person 2 Age: " + person1.equals(person2)); // use the equals method to compare the two people
    }
}
EqualsNoOverride.main(null)

Person 1 equals Person 2: false

False is returned when you use the boolean equals(Object other) because the parameters is of Type Object superclass is unable to detect them since the Object class saves them under two different memory addresses and to fix this, we have to make an override method for this.

To do this, we use instanceof and casting

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    @Override // We override the equals method
    public boolean equals(Object other) {
        if (!(other instanceof Person)) // Using instanceof, we are making sure that the we compare objects of the same class
            return false;
        Person that = (Person) other; // Here we perform casting to make sure that other is converted to Person
        return this.age == that.age;
    }

    @Override
    public String toString() {
        return "Person Name: " + name + "\nPerson Age: " + age;
    }
}

public class EqualsOverride {
    public static void main(String[] args) {
        Person person1 = new Person("Alice", 25);
        Person person2 = new Person("Bryce", 25);

        System.out.println("Person 1 Age equals Person 2 Age: " + person1.equals(person2));
    }
}
EqualsOverride.main(null)

Person 1 Age equals Person 2 Age: true

Hacks

Create a superclass with at least 2 subclasses based on your own topic.

Create a DrawIO diagram for your structure and label them with superclasses and subclasses
Create a superclass on your own topic
Create at least two subclasses
Each class must create at least two methods, one private and public variable, and examples of local, static, instance, and parameter variables
Override at least one method
Use the super keyword at least once

class Shape {
    protected String color;
    private String name;

    public Shape(String name, String color) {
        this.name = name;
        this.color = color;
    }

    public double calculateArea() {
        return 0.0; // Placeholder, to be overridden by subclasses
    }

    private void printInfo() {
        System.out.println("Shape Name: " + name);
        System.out.println("Color: " + color);
    }
}

class Rectangle extends Shape {
    private double length;
    private double width;

    public Rectangle(String color, double length, double width) {
        super("Rectangle", color);
        this.length = length;
        this.width = width;
    }

    @Override
    public double calculateArea() {
        return length * width;
    }

    public double calculatePerimeter() {
        return 2 * (length + width);
    }
}

class Circle extends Shape {
    private double radius;

    public Circle(String color, double radius) {
        super("Circle", color);
        this.radius = radius;
    }

    @Override
    public double calculateArea() {
        return Math.PI * Math.pow(radius, 2);
    }

    public double calculateCircumference() {
        return 2 * Math.PI * radius;
    }
}

public class Main {
    public static void main(String[] args) {
        Shape shape1 = new Rectangle("Blue", 5, 10);
        Shape shape2 = new Circle("Red", 7);

        System.out.println("Shape 1 Area: " + shape1.calculateArea());
        System.out.println("Shape 2 Area: " + shape2.calculateArea());

        // Example of using 'super'
        System.out.println("Shape 1 Color: " + shape1.color);
        // The following line would result in a compilation error since 'name' is private in Shape
        // System.out.println("Shape 1 Name: " + shape1.name);
    }
}

U9 Inheritance P1 Student • 81 min read

Description

9.1 Superclasses and Subclasses

Pre-Requisites

Scope of Variables:

Class Hierarchy

`extends` Keyword

9.2 Writing Constructors for Subclasses

Learning Objectives

Key Reminders:

9.3 Overriding Methods

Learning Objectives

Popcorn Hack

9.4 Super Keyword

Using the super keyword to call a superclass’s method.

Note:

However, if we were to write:

What if we use 2 super keywords?

Popcorn Hack

9.5 Creating References Using Inheritance Hierarchies

Why would we want to do this?

Here is a Complete Example of the Inheritance Hierarchy from above:

9.6 Polymorphism

Learning Objectives

What is Polymorphism?

Popcorn hack

Static and Dynamic types

Compile-time vs Runtime methods

Popcorn Hacks

9.7 Object Superclass

Hacks

9.1 Superclasses and Subclasses

Pre-Requisites

Scope of Variables:

Class Hierarchy

extends Keyword

9.2 Writing Constructors for Subclasses

Learning Objectives

Key Reminders:

9.3 Overriding Methods

Learning Objectives

Popcorn Hack

9.4 Super Keyword

Using the super keyword to call a superclass’s method.

Note:

However, if we were to write:

What if we use 2 super keywords?

Popcorn Hack

9.5 Creating References Using Inheritance Hierarchies

Why would we want to do this?

Here is a Complete Example of the Inheritance Hierarchy from above:

9.6 Polymorphism

Learning Objectives

What is Polymorphism?

Popcorn hack

Static and Dynamic types

Compile-time vs Runtime methods

Popcorn Hacks

9.7 Object Superclass

Hacks

`extends` Keyword